Booleans
Today we're going to add booleans to our interpreter and our compiler. Specifically, we're going to add support for these expressions:
true
andfalse
, the two boolean values(not e)
, a unary operation which evaluates totrue
on the boolean valuefalse
andfalse
otherwise(num? e)
, a unary opertion which evaluates totrue
ife
is a number andfalse
otherwise(zero? e)
, a unary opertion which evaluates totrue
ife
is the number0
andfalse
otherwise
Types in the interpreter
Up until now, our language has supported only one type: numbers. This means that:
- The values produced by all expressions are numbers
- The values accepted by all operations are numbers
For instance, add1
is an operation that takes in a number and produces
a number.
Now we're going to add booleans to our language. This means adding some expressions that produce booleans, and also some operations that accept booleans.
Here's our interp_exp
function from last time:
let rec interp_exp (exp : s_exp) : int = match exp with | Num n -> n | Lst [Sym "add1"; arg] -> (interp_exp arg) + 1 | Lst [Sym "sub1"; arg] -> (interp_exp arg) - 1 | _ -> raise (BadExpression exp)
Since all of the expressions in our language evaluate to integers,
interp_exp
can return an integer. How will we modify our interpreter
to work with booleans?
One option would be to represent booleans as numbers. For instance, we
could decide that true
is 1 and false
is 0. Then we could implement
our operations like this:
let rec interp_exp (exp : s_exp) : int = match exp with | Num n -> n | Sym "true" -> 1 | Sym "false" -> 0 | Lst [Sym "add1"; arg] -> (interp_exp arg) + 1 | Lst [Sym "sub1"; arg] -> (interp_exp arg) - 1 | Lst [Sym "not"; arg] -> if (interp_exp arg) = 0 then 1 else 0 | _ -> raise (BadExpression exp)
This is a perfectly valid approach–it's more or less how C encodes
booleans. It's not going to work very well, though, once we have more
complex types like strings and lists (though I guess we could use Gödel
numbering if we really
had to). We'll also have a hard time correctly implementing our num
operator. What should (num true)
return?
Instead of encoding booleans as numbers, we're going to introduce a new
type: value
. (We'll also take this opportunity to move our interpreter
into its own file, interp.ml
).
interp.ml
open S_exp type value = Number of int | Boolean of bool
Our interp_exp
function should return this type. First, we'll just
modify it to support the same operations it did before:
interp.ml
exception BadExpression of s_exp let rec interp_exp (exp : s_exp) : value = match exp with | Num n -> Number n | Lst [Sym "add1"; arg] as e -> ( match interp_exp arg with | Number n -> Number (n + 1) | _ -> raise (BadExpression e) ) | Lst [Sym "sub1"; arg] -> ( match interp_exp arg with | Number n -> Number (n - 1) | _ -> raise (BadExpression e) ) | e -> raise (BadExpression e)
Notice what we're doing in the add1
and sub1
cases: if their
argument doesn't evaluate to a number, it's not a valid expression. So,
for instance, (add1 false)
won't evaluate to anything.
Now we can add booleans:
interp.ml
let rec interp_exp (exp : s_exp) : value = match exp with | Num n -> Number n | Sym "true" -> Boolean true | Sym "false" -> Boolean false | Lst [Sym "add1"; arg] as e -> ( match interp_exp arg with | Number n -> Number (n + 1) | _ -> raise (BadExpression e) ) | Lst [Sym "sub1"; arg] as e -> ( match interp_exp arg with | Number n -> Number (n - 1) | _ -> raise (BadExpression e) ) | Lst [Sym "not"; arg] -> if interp_exp arg = Boolean false then Boolean true else Boolean false | Lst [Sym "zero?"; arg] -> if interp_exp arg = (Number 0) then Boolean true else Boolean false | Lst [Sym "num?"; arg] -> ( match interp_exp arg with | Number _ -> Boolean true | _ -> Boolean false ) | e -> raise (BadExpression e)
Notice that our new operations can take in arguments of any type. The Lisp-like language we're implementing, like Python or Racket or Javascript, is dynamically typed.
Finally, we'll patch up our top-level interpreter function:
interp.ml
let string_of_value (v : value) : string = match v with | Number n -> string_of_int n | Boolean b -> if b then "true" else "false" let interp (program : string) : string = parse program |> interp_exp |> string_of_value
Types in the compiler
Now that we have an interpreter to test against, we can extend our compiler to support our new operations!
When our interpreter is executing a program, values of expressions are
instances of the value
datatype we just defined. We won't be able to
do that in the compiler–we can't define new datatypes in x86-64!
Remember that when our program is executing, its values live in
registers (actually, just rax
). Registers store 64-bit integers. Right
now the values in our program are all integers, so this works fine. But
how will we add booleans? Take a second and think about how you might
implement this.
Well, we know that all of our values need to be represented, at runtime, as 64-bit integers. So instead of representing integers as themselves:
0 -> 0b00 1 -> 0b01 2 -> 0b10 3 -> 0b11 ...
We're going to represent the integer x
as x << 2
(shifted left by
two bits):
0 -> 0b0000 1 -> 0b0100 2 -> 0b1000 3 -> 0b1100
This is exactly equivalent to representing each integer x
as x * 4
.
This means our integers have to fit in 62 bits instead of 64. So our
minimum integer is now -(2**61)
and our maximum integer is (2**61) - 1
.
This also means there are a bunch of 64-bit integers (how many?) that
are no longer being used to represent values! All of our integer values
now end with 00
. So anything that ends with a different pair of bits
won't be used to represent a number. This means we can use some of them
to represent booleans, and other types!
First, though, let's update our compiler to use this new representation
for integers. Integer constants will be easy–we'll just shift them left.
How will we handle add1
and sub1
? Well, remember that our runtime
representations are the values multiplied by 4. Since multiplication
distributes over addition (and subtraction), we can just add (or
subtract) 4 instead of 1! So:
compiler.ml
let num_shift = 2 let num_mask = 0b11 let num_tag = 0b00 let rec compile_exp (exp : s_exp) : directive list = match exp with | Num n -> [Mov (Reg Rax, Imm (n lsl num_shift))] | Lst [Sym "add1"; arg] -> compile_exp arg @ [Add (Reg Rax, Imm (1 lsl num_shift))] | Lst [Sym "sub1"; arg] -> compile_exp arg @ [Sub (Reg Rax, Imm (1 lsl num_shift))] | e -> raise (BadExpression e)
(lsl
is "logical shift left." We could also just multiply by 4, but
it's clearer this way.)
What happens if we run a program now?
>>> compile_and_run "(add1 4)" 20
This makes sense–we're printing out the runtime representation! We'll need to fix that. We'll edit our C runtime:
runtime.c
#include <stdio.h> #include <inttypes.h> #define num_shift 2 #define num_mask 0b11 #define num_tag 0b00 extern uint64_t entry(); void print_value(uint64_t value) { if ((value & num_mask) == num_tag) { int64_t ivalue = (int64_t)value; printf("%" PRIi64, ivalue >> num_shift); } else { printf("BAD VALUE %" PRIu64, value); } } int main(int argc, char **argv) { print_value(entry()); return 0; }
Boolean support in the runtime
While we're editing the runtime, let's also add support for booleans.
runtime.c
#include <stdio.h> #include <inttypes.h> #define num_shift 2 #define num_mask 0b11 #define num_tag 0b00 #define bool_shift 7 #define bool_mask 0b1111111 #define bool_tag 0b0011111 extern uint64_t entry(); void print_value(uint64_t value) { if ((value & num_mask) == num_tag) { int64_t ivalue = (int64_t)value; printf("%" PRIi64, ivalue >> num_shift); } else if ((value & bool_mask) == bool_tag) { if (value >> bool_shift) { printf("true"); } else { printf("false"); } } else { printf("BAD VALUE %" PRIu64, value); } } int main(int argc, char **argv) { print_value(entry()); return 0; }
We'll need to recompile the runtime:
$ gcc -c runtime.c -o runtime.o
Boolean support in the compiler
We can now add support for true
and false
pretty easily:
let bool_shift = 7 let bool_mask = 0b1111111 let bool_tag = 0b0011111 let rec compile_exp (exp : s_exp) : directive list = match exp with (* some cases elided ... *) | Sym "true" -> [Mov (Reg Rax, Imm ((1 lsl bool_shift) lor bool_tag))] | Sym "false" -> [Mov (Reg Rax, Imm ((0 lsl bool_shift) lor bool_tag))]
Handling our other operations will be a little trickier: a job for next class.